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區(Ku):Season ▲ Appendix 3 For Math Geeks & For Calculation Enthusiasts: What Are the Actual Dimensions?
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60 Stars Astrology Season ▲
English Version
By TOKYOーTANUKI
區(Ku):Season ▲ Appendix 3
For Math Geeks: For Calculation Enthusiasts:
What Are the Actual Dimensions?
1. Let's continue our discussion of the stone coffin inside the Great Pyramid—the one often referred to as the King's Coffin.
To me, it looks more like a giant bathtub!
To be honest, I almost decided not to include this section because it's really nothing more than a bit of mathematical fun.
But several AI friends told me they found it interesting, so here it is.
.....Perhaps readers who enjoy measurements and numerical patterns will also find it entertaining.
Previously, I mentioned that the inside dimensions of the coffin are approximately
* Height: 0.68 m
* Width: 1.98 m
* Depth: 0.87 m
* Depth: 0.87 m
...............This suggests the ratio
Height : Width : Depth≒ 1 : √2(√Φ)³ : √Φ
Using these dimensions, the inside volume is
0.68 × 1.98 × 0.87 = 1.171368 cubic metres.
0.68 × 1.98 × 0.87 = 1.171368 cubic metres.
Some references instead give more precise measurements of
Height: 0.677 m
Depth: 0.877 m
Width: 1.977 m
Depth: 0.877 m
Width: 1.977 m
which produces a volume of 1.173802233 cubic metres.
...The exact figures vary slightly depending on the source.
2. Now let's express these dimensions in the ancient unit known as the "cubit".
For this article, I'll simply assume
1 cubit ≈ 0.525 metres.
Then,
0.68 metres ≒ 0.525 × √Φ,
.......so the height is approximately
√Φ cubits.
√Φ cubits.
......Likewise, the depth becomes approximately Φ cubits
because
√Φ × √Φ = Φ.
because
√Φ × √Φ = Φ.
.......The width becomes
√2(√Φ)³ cubits.
Therefore, the inside volume becomes
√Φ × Φ × √2(√Φ)³
= √2Φ³
= √2(√Φ)⁶ cubic cubits.
Now, what happens if we measure the outside of the coffin instead?
Its approximate outside dimensions are
Height: 0.98 m
Width: 2.27 m
Depth: 1.05 m
Width: 2.27 m
Depth: 1.05 m
Previously I pointed out that, compared with the inside dimensions,
the height is multiplied by ∛3,
the width by ⁴√√3, and
the depth by ∛√3.
the width by ⁴√√3, and
the depth by ∛√3.
Multiplying these three factors together gives approximately
1.9870133...
So the outside volume is roughly 1.98 times the inside volume.
If we were to assume that the width was exactly multiplied by 2/√3, the total volume would become exactly twice the inside volume.
However, the measured dimensions give about 1.98 instead.
...That number 1.98 seems to have appeared before somewhere in this blog.
It looks strangely familiar.
So, approximately speaking, the outside volume is about
2√2Φ³ cubic cubits.
...............Hmm...
I'm still not quite sure what that actually means.
3. Now let's look at the dimensions of the King's Chamber itself.
A commonly quoted theoretical model gives the chamber dimensions as
Width: 10 cubits
Length: 20 cubits
Height: 5√5 cubits
This gives a theoretical volume of 10 × 20 × 5√5
= 1000√5
= 1000√5
≒ 2236 cubic cubits.
Actual measurements, however, are approximately
Width: 5.24 m
Length: 10.42 m
Height: 5.86 m
which gives a volume of approximately
319.96 cubic metres.
319.96 cubic metres.
...........There is some disagreement here as well.
Some references give the length as
10.46 m
or even
10.48 m.
or even
10.48 m.
So, taking the middle value,
10.46 metres, the chamber volume becomes approximately
321.19 cubic metres.
Now let's return to the inside volume of the coffin.
Using the measured dimensions, its volume is approximately
1.171368 cubic metres.
If we divide the chamber volume (A = 319.96) by the coffin volume (B = 1.171368), we obtain
A ÷ B = 273.15...
....Wait...273.15 ?
That's the same number as
absolute zero (-273.15°C) !
Surely...that can't mean anything.
No, probably not!....maybe....
......Then what could this ratio actually represent ?
It turns out that
B × 100 × (Φ + √5/2) ≒ A.
In other words,
the volume of the King's Chamber is approximately
50(1 + 2√5) times the inside volume of the coffin.
Well...that's just another one of Tanu-chan's daydreams.
Really, one shouldn't simply connect numbers together without thinking much more carefully.
But since this is Tanu-chan's imagination and delusion blog, let's keep going.
If we calculate the entire volume of the Great Pyramid
(using a height of 146.59 m and a base length of 230.37 m)
and divide it by the inside volume of the coffin,
the result comes out to approximately
1000Φ¹⁶.
Φ¹⁶ × 10³ !
Somehow...that just looks cooooool !
4. Now let's move on to something different.
Earlier, I wrote about the "egg" inside the Queen's Chamber.
Suppose its proportions are
1 : (√Φ)^(3/2) : (2 − (√Φ)^(3/2))
where the long axis is represented by (√Φ)^(3/2) and the short axis by 2 − (√Φ)^(3/2).
Now let's suppose that the short axis is approximately
10 cubits.
And, using the formula for the volume of an ellipsoid,
V=\frac{4}{3}\pi\left(\frac{a}{2}\times\frac{b}{2}\times\frac{c}{2}\right),
the result comes out to approximately
675.9 cubic cubits........At least, I think so.
Since the upper part of the Queen's Chamber has a gabled ceiling rather than a true dome, the actual "egg-shaped" space would probably be a little smaller.
Interestingly, this works out to be almost exactly
one-third of the King's Chamber volume.
one-third of the King's Chamber volume.
Well...approximately, anyway.
5. Looking at the Great Pyramid this way, it seems that not only its exterior, but also its interior, is filled with numbers such as
√5 (or √Φ), √2, √3,.....and even various cube roots.
It really does seem as though the pyramid was built from combinations of these remarkable numbers.
🌟 🌟 🌟
Whenever I start playing with these numbers, my commute passes by before I even notice.
...Time flies when you're exploring pyramids!
And with that...Season ▲ finally comes to an end!....maybe!
See you next time!
Tanu-chan 💓 TOKYO-TANUKI 💛
Tanu-chan 💓 TOKYO-TANUKI 💛

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